JEE MAIN - Physics (2022 - 25th June Morning Shift - No. 6)
The terminal velocity (vt) of the spherical rain drop depends on the radius (r) of the spherical rain drop as :
r1/2
r
r2
r3
Explicació
$$6\pi \eta {v_t}r = {4 \over 3}\pi {r^3}(\rho - \sigma )g$$
$$ \Rightarrow {v_t} = C{r^2}$$ where C is a constant
or $${v_t} \propto {r^2}$$